A bar magnet of moment of inertia `9 xx 10^(-5) kg m^2` placed in a vibration magnetometer and oscillating in a uniform magnetic field `16pi^2 xx 10^(-5) T` makes 20 oscillations in 15 s. The magnetic moment of the bar magnet is:

Options

A. `3Am^2`
B. `2Am^2`
C. `5Am^2`
D. `6Am^2`

Explanation

To find the magnetic moment of the bar magnet, we can follow these steps:

### Step 1: Calculate the Time Period of Oscillation
The time period \( T \) can be calculated using the formula:
\[ T = \frac{\text{Total time}}{\text{Number of oscillations}} \]
Given that the total time is 15 seconds and the number of oscillations is 20, we have:
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