Explain quantitatively the order of magnitude difference between the diamagnetic susceptibility of `N_2(-5xx10^-9)` (at STP) and `Cu(-10^-5)`.

Explanation

Magnetic susceptibility is given by:
`chi = (I_m)/(H) = (M)/(VH)`
Where `I_m` = Intensity of magnetization , H = Magnetic intensity , M = Magnetic moment , V = Volume
` rArr chi prop 1/V`
`rArr xhi = rho `
where `rho ` is the density
`(rho_( N_2))/(rho_(Cu)) = (28 g//22.4 l)/(8g/"cc") = (28g//22.4 xx 1000 "cc")/(8g//"cc") = 1.6 xx 10^(-4)`
From the given information:
`(chi_(N_2) )/(chi_(Cu)) = (5 xx 10^(-9) )/(10^(-5) ) = 5 xx 10^(-4)`
From the above two relations, we can say that there is a major difference in the magnitude of susceptibility of `N_2` and Cu due to a large difference in their densities.