An emf `epsilon=220` sin 50 `pi` t is applied to a circuit which consistas of an inductance of `(1)/(2pi)` H. Write an equation for instantaneous current in the circuit . Calculate the reading of an AC ammeter when it is connected in the circuit .

Explanation

To solve the problem, we need to find the instantaneous current in the circuit and the reading of the AC ammeter when connected. Let's break it down step by step.

### Step 1: Identify the given values
- The EMF is given as:
\[ \epsilon(t) = 220 \sin(50 \pi t) \]
- The inductance \( L \) is given as:
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