A capacitor of capacitance 2 `muF ` is connected to an osillator giving an output voltage e = 20 sin `omega` t volt . If `omega = 10 pi ` rad/ s write an equation for instantaneous current through the circuit .

Explanation

To find the instantaneous current through a capacitor connected to an AC source, we can follow these steps:

### Step 1: Identify the given values
- Capacitance \( C = 2 \, \mu F = 2 \times 10^{-6} \, F \)
- Voltage \( e(t) = 20 \sin(\omega t) \)
- Angular frequency \( \omega = 10 \pi \, \text{rad/s} \)

### Step 2: Write the expression for the capacitive reactance \( X_c \)
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