A capacitor and an inductor coil are connected in series with one AC source of rms voltage 24 V and variable frequency . Maximum current that we get is 6A by changing the frequency of the source . Now the inductor coil is taken out from the circuit and separated connected to a DC source of 12 V and internal resistance 8 `Omega` . Find the current drawn from the battery by the inductor coil.

Explanation

To solve the problem step-by-step, we will follow the reasoning provided in the video transcript and apply the relevant formulas.

### Step 1: Understand the AC Circuit
In the AC circuit, the capacitor and inductor are connected in series with an AC source of RMS voltage 24 V. The maximum current (I_max) is given as 6 A. This maximum current occurs at resonance, where the inductive reactance (X_L) equals the capacitive reactance (X_C).

### Step 2: Calculate the Resistance of the Inductor Coil
At resonance, the impedance (Z) of the circuit is equal to the resistance (R) of the inductor coil. The relationship between voltage (V), current (I), and impedance (Z) is given by:
\[
...