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A resistor of resistance 400 Omega and i...

A resistor of resistance 400 `Omega` and inductor of inductacne 100 mH are connected imn series along with variable capacitor . Frequency of AC source is 1000 Hz. What magnitude of capacitance is required to generate maximum current in the circuit ?

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To solve the problem, we need to find the capacitance required to generate maximum current in a series LCR circuit consisting of a resistor (R), an inductor (L), and a variable capacitor (C). The condition for maximum current is that the circuit must be in resonance, which occurs when the inductive reactance (XL) equals the capacitive reactance (XC). ### Step-by-Step Solution: 1. **Identify the given values:** - Resistance (R) = 400 Ω - Inductance (L) = 100 mH = 100 × 10^(-3) H - Frequency (f) = 1000 Hz ...
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MODERN PUBLICATION-ALTERNATING CURRENT -CHAPTER PRACTICE TEST
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  2. Write the relation between the rms value and peak value of AC.

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  6. Why do we prefer a choke coil to a rhestat in controlling a.c.?

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  10. An electric heater is connected to DC and AC sources of equal voltage ...

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  11. Under which condition the current will lag behind the voltage? Explain...

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  12. When an ac source is connected to an ideal capacitor, show that the av...

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  13. Show that in the free oscillations of an LC circuit, the sum of energi...

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  14. Can the voltage drop across the inductor or capacitro in a series LCR ...

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  15. An alternating voltage given by V = 240 sin 314 t is connected across ...

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  16. What is power factor of an LCR circuit ? Explain on the basis of power...

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  17. (a) In a series LCR circuit connected across an AC source of varible f...

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