A capacitor of 50 `muF` is first charged with a 100 V supply connected across it and then after the supply is removed it is connected across an inductor . As a result a maximum current of 2 A flows through the inductance . What is the value of inductance ?

Explanation

To solve the problem, we need to find the inductance \( L \) of the inductor after the capacitor has been charged and then connected to the inductor. We will use the energy conservation principle, where the energy stored in the capacitor is equal to the energy stored in the inductor.

### Step-by-Step Solution:

1. **Identify the given values:**
- Capacitance of the capacitor, \( C = 50 \, \mu F = 50 \times 10^{-6} \, F \)
- Voltage across the capacitor, \( V = 100 \, V \)
- Maximum current through the inductor, \( I = 2 \, A \)
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