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A capacitor of capacitance 10 muF is co...

A capacitor of capacitance 10` muF ` is connected to a 220 V , 30 Hz alternating current source . Calculate the peak value of voltage across the capacitor . Also calculate the rms value of current in the circuit .

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To solve the problem step by step, we will first calculate the peak value of voltage across the capacitor and then calculate the RMS value of current in the circuit. ### Step 1: Calculate the Peak Value of Voltage Across the Capacitor The relationship between the peak voltage (\( V_0 \)) and the RMS voltage (\( V_{RMS} \)) for a sinusoidal AC supply is given by the formula: \[ V_0 = V_{RMS} \times \sqrt{2} \] Given: - \( V_{RMS} = 220 \, V \) Substituting the value into the formula: \[ V_0 = 220 \, V \times \sqrt{2} \] Calculating \( \sqrt{2} \): \[ \sqrt{2} \approx 1.414 \] Now, substituting this value: \[ V_0 = 220 \times 1.414 \approx 311.08 \, V \] Thus, the peak value of voltage across the capacitor is approximately: \[ \boxed{311.08 \, V} \] ### Step 2: Calculate the RMS Value of Current in the Circuit To find the RMS current (\( I_{RMS} \)), we first need to calculate the capacitive reactance (\( X_C \)). The formula for capacitive reactance is: \[ X_C = \frac{1}{2 \pi f C} \] Where: - \( f = 30 \, Hz \) - \( C = 10 \, \mu F = 10 \times 10^{-6} \, F \) Substituting the values into the formula: \[ X_C = \frac{1}{2 \pi \times 30 \times 10 \times 10^{-6}} \] Calculating \( 2 \pi \): \[ 2 \pi \approx 6.2832 \] Now substituting this value: \[ X_C = \frac{1}{6.2832 \times 30 \times 10 \times 10^{-6}} \approx \frac{1}{1.884 \times 10^{-4}} \approx 5307.96 \, \Omega \] Now that we have \( X_C \), we can calculate the RMS current using the formula: \[ I_{RMS} = \frac{V_{RMS}}{X_C} \] Substituting the values: \[ I_{RMS} = \frac{220 \, V}{5307.96 \, \Omega} \approx 0.0415 \, A \] Thus, the RMS value of current in the circuit is approximately: \[ \boxed{0.0415 \, A} \] ### Summary of Results - Peak Value of Voltage: \( 311.08 \, V \) - RMS Value of Current: \( 0.0415 \, A \)
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MODERN PUBLICATION-ALTERNATING CURRENT -PRACTICE PROBLEMS
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