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A square coil of side 10 cm is rotating ...

A square coil of side 10 cm is rotating about its vertical axis in a region of uniform magnetic field of 0.2 T. The angular speed of coil is 35 rad `s^(-1)`. Calculate the rms value of emf induced in the coil. Also find the power dissipated if resistance of coil is 6 `omega` . Number of turns in coil is 10.

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To solve the problem, we will follow these steps: ### Step 1: Calculate the area of the square coil The side length of the square coil is given as 10 cm. We need to convert this to meters for our calculations. \[ \text{Side length} = 10 \, \text{cm} = 0.1 \, \text{m} \] The area \( A \) of the square coil is given by: \[ A = \text{side}^2 = (0.1 \, \text{m})^2 = 0.01 \, \text{m}^2 \] ### Step 2: Use the formula for induced EMF The induced EMF (\( E \)) in a rotating coil in a magnetic field can be calculated using the formula: \[ E = N \cdot B \cdot A \cdot \omega \cdot \sin(\theta) \] Where: - \( N \) = number of turns = 10 - \( B \) = magnetic field strength = 0.2 T - \( A \) = area of the coil = 0.01 m² - \( \omega \) = angular speed = 35 rad/s - \( \theta \) = angle between the magnetic field and the area vector (maximum value is when \( \sin(\theta) = 1 \)) ### Step 3: Calculate the peak EMF Substituting the values into the formula for peak EMF: \[ E_0 = N \cdot B \cdot A \cdot \omega \] \[ E_0 = 10 \cdot 0.2 \cdot 0.01 \cdot 35 \] Calculating this gives: \[ E_0 = 10 \cdot 0.2 \cdot 0.01 \cdot 35 = 0.07 \, \text{V} \] ### Step 4: Calculate the RMS value of the induced EMF The RMS value of the induced EMF is given by: \[ E_{\text{RMS}} = \frac{E_0}{\sqrt{2}} \] Substituting the peak EMF into this formula: \[ E_{\text{RMS}} = \frac{0.07}{\sqrt{2}} \approx 0.0495 \, \text{V} \approx 0.05 \, \text{V} \] ### Step 5: Calculate the power dissipated in the coil The power \( P \) dissipated in the coil can be calculated using: \[ P = \frac{E_{\text{RMS}}^2}{R} \] Where \( R \) is the resistance of the coil, given as 6 ohms. Substituting the values: \[ P = \frac{(0.05)^2}{6} = \frac{0.0025}{6} \approx 0.00041667 \, \text{W} \approx 0.00042 \, \text{W} \] ### Final Answers - The RMS value of the induced EMF is approximately **0.05 V**. - The power dissipated in the coil is approximately **0.00042 W**.
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