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A 44 mH inductor is connected to 220 V, ...

A 44 mH inductor is connected to 220 V, 50 Hz a.c. supply. Determine rms value of current in the circuit.

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Given, Self-inductance, L = 44 mH = 44 `xx 10^(-3)` H
rms value of voltage , `E_(rms) = 220`, V
frequency, f 50 Hz
rms value of current is given by
`I_(rms) = (E_(rms))/(X_(L)) = (220)/(omega L)`
` therefore " " I_(rms) = (220)/(2 pi f L).`
` rArr " " I_(rms) = (220 )/( 2 xx 3.142 xx 50 xx 44 xx 10^(-3)) = 15.9` A
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