Draw the effective equivalent circuit of the circuit show in Fig. at very high frequencies and find the effective impedance.

Explanation

At very frequency, reactance of the capacitor is
`X_(C) = (1)/(omega C) rarr ` 0
So, capacitor will behave as short circuit. On the other hand, reactance of inductor is
`X_(L) = omega L rarr infty`
so, inductor will behave as open circuit elements. the equivalent circuit will become as follows :