An AC source is rated as 220 V-50 Hz. What will be the peak voltage of this source ?

Options

A. Approximately 110 V
B. Approximately 310 V
C. 220 V
D. 440 V

Explanation

To find the peak voltage (V₀) of an AC source rated at 220 V (RMS voltage), we can use the relationship between RMS voltage and peak voltage. The formula is:

\[ V₀ = V_{rms} \times \sqrt{2} \]

### Step-by-Step Solution:

1. **Identify the given values:**
- The RMS voltage (Vₘₛ) is given as 220 V.

2. **Use the formula for peak voltage:**
- The relationship between peak voltage (V₀) and RMS voltage (Vₘₛ) is:
\[ V₀ = V_{rms} \times \sqrt{2} \]

3. **Substitute the given RMS voltage into the formula:**
- Substitute 220 V for Vₘₛ:
\[ V₀ = 220 \, V \times \sqrt{2} \]

4. **Calculate the value of \(\sqrt{2}\):**
- The approximate value of \(\sqrt{2}\) is 1.414.

5. **Perform the multiplication:**
- Now calculate:
\[ V₀ = 220 \, V \times 1.414 \]
\[ V₀ \approx 311.08 \, V \]

6. **Round the answer:**
- The peak voltage is approximately 311 V.

### Final Answer:
The peak voltage of the AC source is approximately **311 V**.