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A coil of resistance 300 Omega and induc...

A coil of resistance `300 Omega` and inductance 1.0 henry is connected across an voltages source of frequency `300//2pi Hz`. The phase difference between the voltage and current in the circuit is

A

current lags behind voltage be `pi`/4.

B

current leads the voltage by `pi`/4.

C

current lags behind voltage by `pi`/2.

D

current leads the voltage by `pi`/2.

Text Solution

Verified by Experts

The correct Answer is:
A

(a) Angular frequency
`omega = 2piv = 300 `rad /s .

Reactance of inductor can be written as `X_(L)= omegaL`
`300xx1 = 300 Omega` .
`tan delta= 1 implies delta= pi//4 ` .
Here current is lagging behind the voltage because impedance is below resistance .
Hence option (a) is correct .
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