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A series R-C combination is connected to...

A series R-C combination is connected to an AC voltage of angular frequency `omega = 500` rad/s. If the impedance of the R-C circuit is `R sqrt(1.25)` , the time constant (in millisecnd ) of the circuit is

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To find the time constant of the series R-C circuit connected to an AC voltage source, we can follow these steps: ### Step 1: Understand the given information We are given: - Angular frequency, \( \omega = 500 \, \text{rad/s} \) - Impedance, \( Z = R \sqrt{1.25} \) ### Step 2: Write the expression for impedance in an R-C circuit In a series R-C circuit, the impedance \( Z \) is given by: \[ Z = \sqrt{R^2 + X_C^2} \] where \( X_C \) is the capacitive reactance, defined as: \[ X_C = \frac{1}{\omega C} \] ### Step 3: Substitute \( X_C \) into the impedance formula Substituting \( X_C \) into the impedance formula gives: \[ Z = \sqrt{R^2 + \left(\frac{1}{\omega C}\right)^2} \] ### Step 4: Set up the equation using the given impedance We know that: \[ Z = R \sqrt{1.25} \] Thus, we can equate the two expressions for impedance: \[ R \sqrt{1.25} = \sqrt{R^2 + \left(\frac{1}{\omega C}\right)^2} \] ### Step 5: Square both sides to eliminate the square root Squaring both sides leads to: \[ R^2 \cdot 1.25 = R^2 + \left(\frac{1}{\omega C}\right)^2 \] ### Step 6: Rearrange the equation Rearranging gives: \[ R^2 \cdot 1.25 - R^2 = \left(\frac{1}{\omega C}\right)^2 \] \[ 0.25 R^2 = \left(\frac{1}{\omega C}\right)^2 \] ### Step 7: Solve for \( RC \) Taking the square root of both sides: \[ \sqrt{0.25} R = \frac{1}{\omega C} \] \[ 0.5 R = \frac{1}{\omega C} \] Thus, \[ RC = \frac{1}{0.5 \omega} \] ### Step 8: Substitute the value of \( \omega \) Substituting \( \omega = 500 \, \text{rad/s} \): \[ RC = \frac{1}{0.5 \times 500} = \frac{1}{250} \, \text{s} \] ### Step 9: Convert to milliseconds To convert seconds to milliseconds: \[ RC = \frac{1}{250} \times 1000 = 4 \, \text{ms} \] ### Step 10: State the time constant The time constant \( \tau \) of the circuit is: \[ \tau = RC = 4 \, \text{ms} \] ### Final Answer The time constant of the circuit is \( 4 \, \text{milliseconds} \). ---

To find the time constant of the series R-C circuit connected to an AC voltage source, we can follow these steps: ### Step 1: Understand the given information We are given: - Angular frequency, \( \omega = 500 \, \text{rad/s} \) - Impedance, \( Z = R \sqrt{1.25} \) ### Step 2: Write the expression for impedance in an R-C circuit ...
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