Light is falling on a surface of area `3m^2` normal to it . Energy flux of light is `10^6 ` W/m`""^2` . .find the avaerage force exerted on the surface in a time interval of 100 seconds assume that surface is completely reflecting .

Explanation

To find the average force exerted on a surface when light is falling on it, we can follow these steps:

### Step-by-Step Solution:

1. **Identify Given Values**:
- Area of the surface, \( A = 3 \, \text{m}^2 \)
- Energy flux (intensity of light), \( S = 10^6 \, \text{W/m}^2 \)
- Speed of light, \( c = 3 \times 10^8 \, \text{m/s} \)
...