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A parallel plate capacitor is connected ...

A parallel plate capacitor is connected to an ideal battery of emf E through a resistance R and a switch. Area of the plates of capacitor is A, and d is the separation between them. Resistance to the displacement current can be defined as `R_d = V//i_d`, where V and `i_d` are instantaneous potential difference between the plates and displacement current, respectively. Find displacement resistance as a function of time.

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To find the displacement resistance \( R_d \) as a function of time for a parallel plate capacitor connected to an ideal battery through a resistance \( R \), we can follow these steps: ### Step-by-Step Solution 1. **Understand the Setup**: We have a parallel plate capacitor connected to a battery of emf \( E \) through a resistor \( R \). The area of the plates is \( A \) and the separation between them is \( d \). 2. **Capacitance of the Parallel Plate Capacitor**: The capacitance \( C \) of the parallel plate capacitor is given by: \[ ...
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A capacitor of capacitance C is connected to a battery of emf V through a resistance R with a switch connected in series .Switch is turned on at t=0 . Find the displacement current flowing between the plates of capacitor as a function of time .

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Knowledge Check

  • Displacement current is produced between the plates of a capacitor when potential difference between the plates

    A
    is maximum
    B
    is minimum
    C
    is zero
    D
    is changing with time
  • Displacement current exists between the plates of capacitor , when charge of the capacitor

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    B
    increase
    C
    decreases
    D
    zero
  • The capacity of a parallel plate air capacitor is 2 mu F and voltage beteen the plates is changing at the rate of 3 v/s the displacement current in the capacitor is

    A
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    B
    `3 mu A`
    C
    `5 muA`
    D
    `6 muA`
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