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Use the formula lambdamT=0.29cmK to obta...

Use the formula `lambda_mT=0.29cmK` to obtain the characteristic temperature ranges for different parts of the e.m. spectrum. What do the number that you obtain tell you?

Text Solution

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Here ` lamda_m T= 0.29 cm K`
` therefore T = ( 0.29 )/( lamda _m) K`
If ` lamda= 10 ^(-6) m = 10 ^(-4) cm `, then
` T= ( 0.29 )/( 10 ^(-4) = 2900 K`
Similarly temperature for other wavelength can be found .
These numbers provide the temperature ranges required for obtaining radiataions in the various parts of electromagnetic spectrum . If we consider visible radiation of wavelength `lamda = 5 xx 10 ^(-5)` m .
then ` t= ( 0.29 )/( 5xx 10^(-5) ~= 5800 K`
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