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An EM wave radiates out wards from a dip...

An `EM` wave radiates out wards from a dipole antenna with `E_(0)` as the amplitude of its electric filed vector. The electric field `E_(0)` which transports significant energy from the source falls off as

A

`(1)/(r^3)`

B

`(1)/(r^2)`

C

`(1)/(r )`

D

remains constant.

Text Solution

Verified by Experts

The correct Answer is:
C
Since the intensity is inversely propartional to the square of the distance `.r.` from the antiena , i.e,
` I prop =(1 )/( r^2)`
` therefore ` The ampleitude of electric field vector `(E_0)` , which transports signficant energy from the source falls off as
`E_0 prop 1/r`
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