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An e.m. wave travels in vacuum along z d...

An e.m. wave travels in vacuum along z direction:
`vecE=(E_1hati+E_2hatj)cos (kz-omega)`. Choose the correct option from the following :

A

The associated magnetic field is given as ` vecB = 1/c (E_1 hati + E_2 hatj ) cos (kz - omega t ) `

B

the associated magnetic field is given as ` vecB = 1/c ( E_1 hati -E_2 hatj ) cos (kz - omega t).`

C

The given electromagnetic field is circularly polarised .

D

the given electromagnetic wave is plane polarised

Text Solution

Verified by Experts

The correct Answer is:
A, D

The electric field vector is given by
`vecE = ( E_1 hati +E_2 hatj ) cos ( kz - omega t)`
the associated magnetic field vector will be thus given by
` vecB = ( vecE )/(c )= (( E_1 hati +E_2 hatj)/( c) ) cos ( kz - omega t)`
hence , option (a) is correct .
when electric field and magnetic fields are in same phase then wave is called plane polarised . when there is a plane difference of ` pi //2` between electric and magnetic field then wave is called circularly polarised . IF we select option (a) as correct then given wave is plane polarised
the correct options are (a) and (d) .
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