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In Young's double-slit experiment, inter...

In Young's double-slit experiment, interference pattern is observed at a distance of 1m. If light used has a frequency of `6 xx 10^(14)` Hz and slit separation distance is equal to 0.05 mm, calculate the distance between fourth bright fringe and centre.

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To solve the problem of finding the distance between the fourth bright fringe and the center in Young's double-slit experiment, we can follow these steps: ### Step 1: Find the Wavelength of the Light We know the relationship between the speed of light (c), frequency (f), and wavelength (λ) is given by the equation: \[ c = f \lambda \] Where: - \( c = 3 \times 10^8 \, \text{m/s} \) (speed of light) - \( f = 6 \times 10^{14} \, \text{Hz} \) Rearranging the equation to find the wavelength: \[ \lambda = \frac{c}{f} \] Substituting the values: \[ \lambda = \frac{3 \times 10^8}{6 \times 10^{14}} \] Calculating this gives: \[ \lambda = 0.5 \times 10^{-6} \, \text{m} \] \[ \lambda = 5 \times 10^{-7} \, \text{m} \] ### Step 2: Use the Formula for the Distance of the nth Bright Fringe The distance of the nth bright fringe from the center (central maximum) is given by the formula: \[ y_n = \frac{n \lambda D}{d} \] Where: - \( y_n \) = distance of the nth bright fringe from the center - \( n \) = order of the fringe (for the fourth bright fringe, \( n = 4 \)) - \( D \) = distance from the slits to the screen (given as 1 m) - \( d \) = slit separation (given as 0.05 mm = \( 0.05 \times 10^{-3} \, \text{m} \)) ### Step 3: Substitute the Values into the Formula Now, substituting the values into the formula for the fourth bright fringe: \[ y_4 = \frac{4 \times (5 \times 10^{-7}) \times 1}{0.05 \times 10^{-3}} \] Calculating this step-by-step: 1. Calculate the numerator: \[ 4 \times (5 \times 10^{-7}) = 20 \times 10^{-7} = 2 \times 10^{-6} \, \text{m} \] 2. Calculate the denominator: \[ 0.05 \times 10^{-3} = 5 \times 10^{-5} \, \text{m} \] 3. Now divide the numerator by the denominator: \[ y_4 = \frac{2 \times 10^{-6}}{5 \times 10^{-5}} = \frac{2}{5} \times 10^{-1} = 0.4 \, \text{m} \] ### Step 4: Convert to Millimeters Since the question may require the answer in millimeters: \[ y_4 = 0.4 \, \text{m} = 40 \, \text{mm} \] ### Final Answer The distance between the fourth bright fringe and the center is: \[ \text{Distance} = 40 \, \text{mm} \] ---
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  8. In Y.D.S.E. , distance between both the slits is 2 mm. When a light of...

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  10. In Y.D.S.E., light of wavelength 5500 Å is used. If the slits are at a...

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  11. Two slits are made one millimeter apart and the screen is placed one m...

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  14. In Young's double-slit, experiment, light of 6000 Å is used. What will...

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  17. In Y.D.S.E., light of wavelength 600 nm is used. When slits are 1.2 mm...

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