Young's double-slit experiment is performed in a medium with refractive index greater than that of air. How will the interference pattern differ from the one performed in air as the medium?

Explanation

When Young.s double-slit experiment will be performed in the medium with refractive index greater than that of air, the wavelength of the light will change to
`lambda. = (lambda_("air"))/("refractive index of medium") implies lambda. < lambda_("air")`
As the wavelength of light decreases, the fringe separation will decrease. Thus interference pattern formed in medium with greater refractive index than that of air will have smaller fringe separation.