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The work function of caesium is 2.14 eV...

The work function of caesium is 2.14 eV . Find (a) the threshold frequency for caesium , and ( b) the wavelength of the incident light if the photocurrent is brought to zero by a stopping potential of 0.60 V.

Text Solution

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The correct Answer is:
(a) `5.16xx10^(14)Hz`
(b) (b) `454 xx10^(-9)m`
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