Light of `5,500 Å` is incident on a metal of work function 2 eV . Calculate the
(i) threshold wavelength
(ii) maximum velocity of electrons emitted.

The work function for calcium is 2.14 eV. When a light of wavelength 5500Å is incident on it, photoelectrons are emitted , Calculate (i) threshold frequency and threshold wavelength. (ii) maximum velocity of the emitted electrons. (iii) change in maximum kinetic energy of the emitted photoelectrons if the intensity of the incident light is doubled. Take : h = 6.6 xx10^(-34) Js m_e-9xx10^(-31) kg c= 3xx10^8m//s

Light of wavelength 500 nm is incident on a metal with work function 2.28 eV . The de Broglie wavelength of the emitted electron is

The work function for a metal whose threshold wavelength is 5000 Å is

The work function of a metal is 4.2 eV , its threshold wavelength will be

The work function for a metal is 1.8eV. Light of 5000Å is incident on it. Calculate (a) threshold frequency and threshold wavelength, (b) maximum kinetic energy of the emitted electrons, (c) maximum velocity of the emitted electrons, (d) if the intensity of the incident light be doubled, then what will be the maximum kinetic energy of the emitted electrons? given, h=6.63xx10^(-34)Js, m_e=9xx10^(-31)kg, c=3xx10^8ms^-1.

A light of 4 eV incident on metal surface of work function phi eV . Another light of 2.5 eV incident on another metal surface of work function phi_2 eV . Find the ratio of maximum velocity of photo electrons (v_1/v_2) .

Light of wavelength 3000Å is incident on a metal surface whose work function is 1 eV. The maximum velocity of emitted photoelectron will be