In the previous problem , which surface will require less energy to emit photoelectrons ?

Explanation

To determine which surface requires less energy to emit photoelectrons, we can analyze the information provided in the problem using Einstein's photoelectric equation.

### Step-by-Step Solution:

1. **Understanding the Given Information**:
- We have two surfaces, X and Y, exposed to radiation of frequency \( \nu = 10^{12} \) Hz.
- The photoelectrons emitted from surface X have zero kinetic energy, while those from surface Y have some positive kinetic energy.

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