A photon electric surface has work function 2 eV. What is the maximum velocity of the photoelectrons ejected by light of wavelength `3,000Å` .

Explanation

To solve the problem step by step, we will use the concepts of the photoelectric effect and the relevant equations.

### Step 1: Understand the given data
- Work function (φ) = 2 eV
- Wavelength (λ) = 3000 Å = 3000 × 10^(-10) m = 3 × 10^(-7) m

### Step 2: Convert the work function from eV to Joules
1 eV = 1.6 × 10^(-19) Joules
...