A particle of mass `1 mg` has the same wavelength as an electron moving with a velocity of `3 xx 10^(6) ms^(-1)`. The velocity of the particle is

Options

A. `9xx10^(-2) ms^(-1)`
B. `3xx10^(-31) ms^(-1)`
C. `2.7xx10^(-21) ms^(-1)`
D. `2.7xx10^(-18) ms^(-1)`

Answer

D

Explanation

For electron `lamda_e=h/(m_ev_e)`

For particle `lamda_p=h/(m_pv_p)`
`m_pv_p=m_ev_e`
`1xx10^(-6)v_p=9.1xx10^(-31)xx3xx10^6`
`v_p=2.73xx10^(-18)m//s`