The wavelength `lamda_(e)` of an electron and `lamda_(p)` of a photon of same energy E are related by

Answer

D

Explanation

`lamda=h/(mv)`
`lamda=h/(sqrt(2mE))" "(becauseE=1/2mv^2)`
`lamda_e=h/(sqrt(2m_eE))" "...(i)`
`lamda_p=(hc)/E" "...(ii)`
From (i) and (ii)
`lamda_p prop lamda_e^2`