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If the kinetic energy of the particle is...

If the kinetic energy of the particle is increase to 16 times its previous value, the percentage change in the de Broglie wavelength of the paarticle is

A

25

B

75

C

60

D

50

Text Solution

Verified by Experts

The correct Answer is:
B

`lamda=h/(sqrt(2mE))`
`lamda.=h/(sqrt(2m(16E)))=1/4lamda`
`1/4lamda`
`((lamda-lamda.)/lamda)=(lamda-1/4lamda)/lamda=3/4` % Change in wavelength `3/4xx100%=75%`
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