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A hydrogen-like atom in its first excite...

A hydrogen-like atom in its first excited state has excitation energy of 91.8 eV. The energy required to remove the electron from its ion is:

A

91.8 eV

B

122.4 eV

C

183.6 eV

D

61.2 eV

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The correct Answer is:
To solve the problem of finding the energy required to remove the electron from a hydrogen-like atom in its first excited state, we can follow these steps: ### Step 1: Understand the Excitation Energy The excitation energy given is 91.8 eV. This energy is the amount required to move the electron from the ground state (n=1) to the first excited state (n=2). ### Step 2: Use the Formula for Energy Levels According to the Bohr model, the total energy \( E_n \) of an electron in a hydrogen-like atom is given by the formula: \[ E_n = -\frac{13.6 Z^2}{n^2} \text{ eV} \] where \( Z \) is the atomic number and \( n \) is the principal quantum number. ### Step 3: Calculate the Energy for n=1 and n=2 1. For \( n=1 \): \[ E_1 = -\frac{13.6 Z^2}{1^2} = -13.6 Z^2 \text{ eV} \] 2. For \( n=2 \): \[ E_2 = -\frac{13.6 Z^2}{2^2} = -\frac{13.6 Z^2}{4} \text{ eV} \] ### Step 4: Relate Excitation Energy to Energy Levels The excitation energy from \( n=1 \) to \( n=2 \) can be expressed as: \[ E_2 - E_1 = 91.8 \text{ eV} \] Substituting the expressions for \( E_1 \) and \( E_2 \): \[ \left(-\frac{13.6 Z^2}{4}\right) - \left(-13.6 Z^2\right) = 91.8 \] This simplifies to: \[ -\frac{13.6 Z^2}{4} + 13.6 Z^2 = 91.8 \] \[ \frac{3}{4} \cdot 13.6 Z^2 = 91.8 \] ### Step 5: Solve for Z^2 To find \( Z^2 \): \[ 13.6 Z^2 = 91.8 \cdot \frac{4}{3} \] Calculating the right side: \[ Z^2 = \frac{91.8 \cdot 4}{3 \cdot 13.6} \] Calculating this gives: \[ Z^2 = \frac{367.2}{40.8} = 9 \] Thus, \( Z = 3 \). ### Step 6: Calculate the Energy Required to Remove the Electron The energy required to remove the electron from the ground state (n=1) to infinity is given by: \[ E = E_\infty - E_1 \] Where \( E_\infty = 0 \) (energy at infinity) and \( E_1 = -13.6 Z^2 \): \[ E = 0 - (-13.6 \cdot 9) = 13.6 \cdot 9 = 122.4 \text{ eV} \] ### Final Answer The energy required to remove the electron from its ion is **122.4 eV**. ---

To solve the problem of finding the energy required to remove the electron from a hydrogen-like atom in its first excited state, we can follow these steps: ### Step 1: Understand the Excitation Energy The excitation energy given is 91.8 eV. This energy is the amount required to move the electron from the ground state (n=1) to the first excited state (n=2). ### Step 2: Use the Formula for Energy Levels According to the Bohr model, the total energy \( E_n \) of an electron in a hydrogen-like atom is given by the formula: \[ ...
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MODERN PUBLICATION-ATOMS -COMPETITION FILE (Objective A(MCQs) )
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