Taking the Bohr radius `a_(0) = 53` pm, the radius of `Li^(++)` ion in its gnround state, on the basis of Bohr's model, will be about.

Options

A. 15.2 pm
B. 11.3 pm
C. 53 pm
D. 17.6 pm

Answer

D

Explanation

The radius of hydrogen-like ion is :
`r_n=(n^2a_0)/Z`
For `Li^(+ +)` in ground state, Z=3 , n=1
`therefore r_1=(1^2xx"53pm")/3`
`rArr r_1` = 17.66 pm