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In the Bohr's model of hydrogen atom, th...

In the Bohr's model of hydrogen atom, the ratio of the kinetic energy to the total energy of the electron in `n^(th)` quantum state is:

A

1

B

`-1`

C

2

D

`1//2`

Text Solution

Verified by Experts

The correct Answer is:
B

Total energy is sum of the potential energy and kinetic energy
T.E. = -2K + K=-K
where K is kinetic energy and -2K is potential energy.
`therefore` ratio of total energy of electron to kinetic energy is `(-K)/K=-1`
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