The ionization enegry of the electron in the hydrogen atom in its ground state is `13.6 ev`. The atoms are excited to higher energy levels to emit radiations of `6` wavelengths. Maximum wavelength of emitted radiation corresponds to the transition between

Options

A. n=3 to n = 1 states
B. n =2 to n = 1 states
C. n = 4 to n = 3 states
D. n =3 to n = 2 states

Answer

C

Explanation

Number of lines =`(n(n-1))/2`
`6=(n(n-1))/2 rArr n=4`

n =4 to n=3,2,1
n=3 to n=2,1
n=2 to n=1
Maximum wavelength of emitted radiation
Corresponds to transition between x=4 to n=3 states , because there is minimum energy difference .