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The wavelength of the first line of Lyma...

The wavelength of the first line of Lyman series for hydrogen atom is equal to that of the second line of Balmer series for a hydrogen-like ion. The atomic number `Z` of hydrogen-like ion is

A

3

B

4

C

1

D

2

Text Solution

Verified by Experts

The correct Answer is:
D

For hydrogen atom
`1/lambda=R(1/1^2-1/2^2)`
For the given hydrogen-like ion
`1/lambda=RZ^2(1/2^2-1/4^2)`
`rArr (1/1^2-1/2^2)=Z^2(1/2^2-1/4^2)`
`rArr` Z=2
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