When an alpha-particle of mass 'm' movin...

When an `alpha-`particle of mass 'm' moving with velocity 'v' bombards on a heavy nucleus of charge 'Ze' its distance of closest approach from the nucleus depends on `m` as :

`1/sqrtm`

`1/m^2`

`m`

`1/m`

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Verified by Experts

The correct Answer is:

When the particle reaches the closest distance of approach, all its kinetic energy gets converted into electrostatic potential energy.
Hence , `1/2mv^2=(KQq)/d`
`rArr d prop 1/m`

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