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Radiation coming from transition n = 2 t...

Radiation coming from transition `n = 2 to n = 1` of hydrogen atoms falls on helium in `n = 1 and n= 2` state. What are the possible transition of helium ions as they absorb energy from the radiation?

A

`n=2 to n=4`

B

`n=2 to n=5`

C

`n = 2 to n=3`

D

`n =1 to n=4`

Text Solution

Verified by Experts

The correct Answer is:
A
Energy released for transition from n=2 to n=1 in hydrogen atom.
`E=13.6Z^2(1/n_1^2-1/n_2^2)`
Here Z=1, `n_1=1, n_2=2`
`E=13.6xx1^2 (1/1^2-1/2^2)=13.6xx3/4` eV
For `He^+` ion Z=2
(a)n=2 to n=4
`E=13.6xx2^2xx(1/2^2-1/4^2)=13.6xx3/4` eV
(b)n=2 to n=5
`E=13.6xx2^2xx(1/2^2-1/5^2)=13.6xx21/25` eV
(c) n=2 to n=3
`E=13.6xx2^2 xx (1/2^2 -1/3^2)=13.6xx5/9` eV
(d)n=1 to n=4
`E=13.6xx2^2 xx(1/1^2-1/4^2)=13.6xx15/4` eV
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