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Some energy levels of a molecule are sho...

Some energy levels of a molecule are shown in the figure. The ratio of the wavelengths `r = lambda_1//lambda_2` is given by -

A

`r=4/3`

B

`r=2/3`

C

`r=3/4`

D

`r=1/3`

Text Solution

Verified by Experts

The correct Answer is:
D
The difference of the energy between two states can be calculated using the following formula :
`DeltaE=(hc)/lambda`
For the photon with wavelength `lambda_1`
`-E-(-2E)=(hc)/lambda_1`
`lambda_1=(hc)/E`
For the photon with wavelength `lambda_2`
`-E-(-"4E"/3)="hc"/lambda_2`
`lambda_2=(3hc)/E`
Hence, the ratio of the wavelengths is given by
`lambda_1/lambda_2=r=1/3 `.
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