The radius of the hydrogen atom in its ground state is `5.3xx10^(-11)` m. The principal quantum number of the final state of the atom is

The radius of hydrogen atom in its ground state is 5.3 xx 10^-11 m . After collision with an electron it is found to have a radius of 21.2 xx 10^-11 m . The principal quantum number of the final state of the atom is.

The radius of hydrogen atom, in its ground state, is of the order of

The radius of hydrogen atom in its ground state is 5.3 xx 10^(-11)m . After collision with an electron, it is found to have a radius of 21.2 xx 10^(-11)m . What is the principal quantum number of the final state of the atom?

The ionization energy of Hydrogen atom in its ground state is……

The radius of hydrogen atom in its ground state is 5.3 xx 10^(-11)m . After collision with an electron it is found to have a radius of 21.2 xx 10^(-11)m . What is the principle quantum number of n of the final state of the atom ?

The radius of hydrogen atom in the ground state is 5.3 xx 10^(-11) m. When struck by an electron, its radius is found to be 21.2 xx 10^(-11) m . The principal quantum number of the final state will be

The radus of hydrogen atom in the ground state 0.53 Å . The radius of Li^(2+) ion (Atomic number = 3) in a similar state is

The energy of a hydrogen atom in its ground state is -13.6 eV. What is the quantum number of the orbit corresponding to the energy level of -0.85 eV?