Home
Class 12
PHYSICS
Consider the fission .(92)U^(238) by fas...

Consider the fission `._(92)U^(238)` by fast neutrons. In one fission event, no neutrons are emitted and the final stable and products, after the beta decay of the primary fragments are `._(58)Ce^(140)` and `._(44)Ru^(99)`. Calculate Q for this fission process, The relevant atomic and particle masses are:
`m(._(92)U^(238))=238.05079u, m(._(58)Ce^(140))=139.90543 u, m(._(34)Ru^(99))=98.90594 u`

Text Solution

Verified by Experts

For the fission
`""_(92)U^(238) + ""_(0)n^(1) to ""_(58)Ce^(100) + ""_(44)Ru^(99) +Q`
`Q=[m(""_(92)U^(238)) + m_(n)-m(""_(58)Ce^(140))-m(""_(44)Ru^(99))]c^(2)`
`=(238.05079 + 1.00867 - 139.90543-98.90594)u xx c^(2)`
`=(239.05946 -238.81137)u xx c^(2)`
`therefore Q=(231.1)` MeV
Promotional Banner

Topper's Solved these Questions

  • NUCLEI

    MODERN PUBLICATION|Exercise NCERT FILE SOLVED (NCERT EXEMPLAR PROBLEMS SUBJECTIVE QUESTIONS) (VERY SHORT ANSWER TYPE QUESTIONS)|5 Videos

  • NUCLEI

    MODERN PUBLICATION|Exercise NCERT FILE SOLVED (NCERT EXEMPLAR PROBLEMS SUBJECTIVE QUESTIONS (SHORT ANSWER TYPE QUESTIONS))|5 Videos

  • NUCLEI

    MODERN PUBLICATION|Exercise NCERT FILE SOLVED (TEXTBOOK EXERCISES)|22 Videos

  • MOVING CHARGES AND MAGNETISM

    MODERN PUBLICATION|Exercise CHAPTER PRACTICE TEST|13 Videos

  • RAY OPTICS AND OPTICAL INSTRUMENTS

    MODERN PUBLICATION|Exercise CHAPTER PRACTICE TEST|14 Videos

Similar Questions

Explore conceptually related problems

Calculate the number of neutrons in the remaining atoms after the emission of an alpha particle from ._(92)U^(238) atom.

The atomic number (A) and mass number (M) of the nuclide formed where three alpha (alpha) and two (beta) particles are emitted from ._(92)^(238)U

Consider the case of bombardment of U^(235) nucleus with a thermal neutron. The fission products are Mo^(95) & La^(139) and two neutrons. Calculate the energy released by one U^(235) nucleus. (Rest masses of the nuclides are U^(235)=235.0439 u, ._(0)^(1)n=1.0087u, Mo^(95)=94.9058 u, La^(139).9061u) .

The atomic number (A) and mass number (M) of the nuclide formed when three alpha (alpha) and 2 beta (beta) particles are emitted from ""_(92)^(238)U is

._(92)U^(238) is a natural alpha -emitter. After alpha -emission the residual nucleus U_(X1) in turn emits a beta -particle to produce another nucleus U_(X2) . Find out the atomic number and mass number of U_(X1) and U_(X2) .

A uranium nucleus ._(92)U^(238) emits and alpha -particle and a beta -particle in succession. The atomic number and mass number of the final nucleus will be

Suppose that a .^(238)U nucleus "swallows" a neutron and then decays not by fission but by beta decay, emitting an electron and a neutrino. Which nuclide remains after this decay: (a) .^(239)Pu , (b) .^(238)Np , (c) .^(239)Np , or (d) .^(238)Pa ?