Calculate the number of electrons, protons and neutrons present in 24 grams of `""_(12)Mg^(24)` and `""_(12)Mg^(26)`.

Explanation

24 g of magnesium contains `6.023 xx 10^(23)` protons For `""_(12)Mg^(24)`
`therefore` 24 g of Mg has `12 xx 6.023 xx 10^(23)` protons `=72.2 xx 10^(23)`
`therefore 24`g of Mg has `12 xx 6.023 xx 10^(23)` electrons
`=72.2 xx 10^(23)`
`therefore 24g` of Mg has `12 xx 6.023 xx 10^(23)` neutrons
`=72.2 xx 10^(23)`
For `""_(12)Mg^(26)`
26 g of Mg has `6.023 xx 10^(23)` atoms
1g of Mg has `(6.023 xx 10^(23))/26 xx 24` atoms
`=5.56 xx 10^(23)` atoms
`therefore` Total number of electrons in 24 g of `""_(12)Mg^(26) = 12 xx 5.56 xx 10^(23) = 66,72 xx 10^(23`
`therefore` Total number of proton in 24 g of `""_(12)Mg^(26)`
`=66.72 xx 10^(23)`

`therefore` total number of proton in 24 g of `""_(12)Mg^(26) = 66.72 xx 10^(23)`
Total number of neutrons in 24 g of `""_(12)Mg^(26)`
`=14 xx 5.56 xx 10^(23) = 77.84 xx 10^(23)`