Thorium `""_(90)th^(228)` is a radioactive substance and decay to a daughter nucleus. This daughter nucleus is also radioactive and further decays itself. The process continues till the formation of `""_(83)Bi^(212)` . Find the total number of a particles and P particles produced in these decays.

Explanation

To solve the problem of determining the total number of alpha (α) particles and beta (β) particles produced during the decay of Thorium-228 to Bismuth-212, we can follow these steps:

### Step 1: Identify the initial and final nuclei
- The initial nucleus is Thorium-228, represented as \( _{90}^{228}\text{Th} \).
- The final nucleus is Bismuth-212, represented as \( _{83}^{212}\text{Bi} \).

### Step 2: Determine the change in atomic number and mass number
- The atomic number of Thorium is 90, and for Bismuth, it is 83.
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