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The gravitational force between a H-atom...

The gravitational force between a H-atom and another particle of mass m will be given by Newton's law: `F=G (M.m)/(r^(2)`, where r is in km and

A

`M=m_("product") + m_("electron")`

B

`M=m_("proton") + m_("electron") -B/c^(2) (B = 13.6eV)`

C

M is not related to the mass of the hydrogen atom.

D

`M=m_("proton") + m_("electron") -(|V|)/c^(2)` (|V|= magnitude of the potential energy of electron in the H-atom).

Text Solution

Verified by Experts

In the given formula, M for H-atom is
`M=m_("proton") + m_("electron") -B/c^(2) (B=13.6 ev)`
where B is the binding energy of the H-atom.
The correct option is (b).
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