A boy throws a ball in air in such a manner that when the ball is in its max. height, he throws another ball. If the balls are thrown after the time difference of 1 s, then what will be the height attained by them:

Options

A. 19.6 m
B. 9.8 m
C. 4.9m
D. 2.45 m

Answer

c

Explanation

Since t=1 s`:. H=(1)/(2)g t^(2)=(1)/(2)xx9.8xx12=4.9 m`