A body is released from the top of a tower of height metre. It takes time T seconds to reach the ground. Where is the body at time `T/2`seconds?

Options

A. At `h/2` m from the ground
B. At `h/4` m from the ground
C. At `3h/4` m from the ground
D. Depend upon mass and volume of the body

Answer

c

Explanation

`h=(1)/(2) g t^(2) implies T^(2)=(2h)/(g)`
In time T/2 `h=(1)/(2)g. (T^(2))/(4)=(1)/(2)g.(1)/(4),(2h)/(g)=(h)/(4)` from top
`:.` Body is at `(h-(h)/(4))=(3h)/(4)` from bottom