A train is moving with a speed of 54 km/h. A monkey is running on the roof of a train against its motion with a speed of 5 ms. w.ut the train. The velocity of the monkey as observed by a man on the ground is :

Options

A. `20 ms^(-1)`
B. `15ms^(-1)`
C. `10ms^(-1)`
D. `5ms^(-1)`

Answer

c

Explanation

`v_t=54km//h`=15 m/s,
vel. Of monkey w.r.t to train `v_(m-t)=-5m//s^(-1)`
`impliesV_(m)-v_(t)=-5 implies v_(m)=+10 m//s`
`:. V_(m,obs)=v_(m)-v_(obs)=10-0=10 m//s`