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A particle moving in straight line cover...

A particle moving in straight line cover half the distance with speed `3 ms^-1`. The other half is covered in two equal time intervals with speed `4.5 ms^-1 and 7.5 ms^-1` respectively. The average speed of the particle during motion is

A

`4 ms^(-1)`

B

`5 ms^(-1)`

C

`5.5 ms^(-1)`

D

`4.5 ms^(-1)`

Text Solution

Verified by Experts

The correct Answer is:
a

Time taken to cover OA`=((x/2))/(3)=(x)/(6)`

Since AB and BC are covered in equal time intervels say `t_2`
`:. 4.5 t_(2)+7.5t_(2)=(x)/(2)implies t_(2)=(x)/(24)`
`:.` Total time taken, `t=(x)/(6)+(x)/(24)+(x)/(24)=(x)/(4)`.
`:.` Average speed =`(x)/(x//4)=4 m//s`
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