A body when released from the top of a tower of height h reaches the ground in time T. At what time it is at a height `h/2`above the ground?

Options

A. `T/2`
B. `T/4`
C. `T/(sqrt(2))`
D. `sqrt(2T)`

Answer

c

Explanation

`h=(1)/(2)g t^(2)`
Now `(h)/(2)=(1)/(2) g t^(2):. (1)/(2)((1)/(2)g t^(2))=(1)/(2) g t^(2)implies t=(t)/(sqrt(2))`