A particle is moving along a straight line path according to the relations `s^(2)=at^(2)+2bt+c`
represent the distance travelled in t seconds and a, b, c are constant. Then the acceleration of the particle varies as:

Options

A. `s^(-3)`
B. `s^(3//2)`
C. `s^(-2//3)`
D. `s^(2)`

Answer

a

Explanation

Here `s^(2)=at^(2)+2bt+c`
Diff.both sides `2d(ds)/(dt)=2a+2b`
or `v=(ds)/(dt)=(2(at+b))/(2s)=(at+b)/(s)`
`f=([as-(at+b)][at+b])/(s^(3)`
or ` fprop s^(-3)`