A body falls from a heighth = 200 m. The ratio of distance travelled in each 2, during != 0 to 6 second of the journey is:

Options

A. `1:4:9`
B. `1:2:4`
C. `1:3:5`
D. `1:2:3`

Answer

c

Explanation

Here applying `s=ut+1//2g t^(2)`
Since body starts from rest u=0
After 2 s the distance travelled is
`s_(2)=(1)/(2)xxgxx(2)^(2)=2g`
After 4s, `s_(4)=(1)/(2)xxgxx(4)^(2)=8g`
After 6s ,`s_6=(1)/(2)xxgxx(6)^(2)=18g`
Distance travellled in first 2 `s=d_1=2g`
Distance travelled in next `2s=d_2=(8-2)g=6g`
Distance travellled in last `2s=d_3(18-8)g=10g`
`:. d_1 :d_2 : d_3 : : 2g :6 g: 10 g`
`therefore 1 : 3: 5`.