A student is standing at a distance of 50 metre from the bus. As soon as the bus begins its motion with an acceleration of `1m//s^(2)`, the student starts running towards the bus with a uniform velocity u. assuming the motion to be along a straight road, the minimum value of u. so that the student is able to catch the bus is

Options

A. `12 m//s^(-1)`
B. `10 m//s^(-1)`
C. `8 m//s^(-1)`
D. `5 m//s^(-1)`

Answer

b

Explanation

Applying `v^(2)-u^(2)=2` as, for the motion of bus
`u=0, a=1 ms^(-2)`
`v^(2)-0=2xx1xx50=100`
`:. V=10 ms^(-1)`
Hence to catch the bus the student should run at least with uniform velocity of `10 ms^(-1)`