The displacement of a particle is given by `x=(t-2)^(2)`  where x is in meters and in seconds. The distance covered by the particle in first 4 seconds is :

Options

A. 4m
B. 8 m
C. 12 m
D. 16 m

Answer

b

Explanation

Here the displacement at any time t is given by
`x=(t-2)^(2)`
Now when t=0
`x_0 =4 m`
This means the particle has an initial displacement of 4 m.
The displacement in first 4 second with be
`x_4 =(4-2)^(2)=4m`
`:.` Total displacement in first 4 seconds will be
`x=x_0 +x_4 =8m`